Two functions f and g are defined on the set of real numbers by \(f : x \to x^{2} + 1\) and \(g : x \to x - 2\). Find f o g.
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Correct Answer: Option B
Explanation:
\(f(x) = x^{2} + 1\) and \(g(x) = x - 2\)
\(f o g = f(g(x)) = f(x - 2) = (x - 2)^{2} + 1 \)
= \(x^{2} - 4x + 4 + 1 = x^{2} - 4x + 5\)
\(f(x) = x^{2} + 1\) and \(g(x) = x - 2\)
\(f o g = f(g(x)) = f(x - 2) = (x - 2)^{2} + 1 \)
= \(x^{2} - 4x + 4 + 1 = x^{2} - 4x + 5\)