A body of mass 28g, initially at rest is acted upon by a force, F Newtons. If it attains a velocity of \(5.4ms^{-1}\) in 18 seconds, find the value of F.
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:
\(F = mass \times acceleration\) but \(accl = \frac{v - u}{t}\)
\(\therefore F = m(\frac{v - u}{t})\)
\(Mass = 28g = 0.028kg\)
\(v = 5.4 ms^{-1}; u = 0; t = 18secs\)
\(\therefore F = 0.028(\frac{5.4 - 0}{18}) = 0.028 \times 0.3 = 0.0084N\)
\(F = mass \times acceleration\) but \(accl = \frac{v - u}{t}\)
\(\therefore F = m(\frac{v - u}{t})\)
\(Mass = 28g = 0.028kg\)
\(v = 5.4 ms^{-1}; u = 0; t = 18secs\)
\(\therefore F = 0.028(\frac{5.4 - 0}{18}) = 0.028 \times 0.3 = 0.0084N\)