A ball falls from a height of 18m above the ground. Find the speed with which the ball hits the ground. \([g = 10ms^{-2}]\)
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Correct Answer: Option D
Explanation:
Due to conservation of energy, K.E = P.E
\(\frac{1}{2}mv^{2} = mgh\)
\(\implies m \times 10 \times 18 = \frac{1}{2}mv^{2}\)
\(v^{2} = 2 \times 10 \times 18 = 360\)
\(v = \sqrt{360} = 18.97ms^{-1}\)
Due to conservation of energy, K.E = P.E
\(\frac{1}{2}mv^{2} = mgh\)
\(\implies m \times 10 \times 18 = \frac{1}{2}mv^{2}\)
\(v^{2} = 2 \times 10 \times 18 = 360\)
\(v = \sqrt{360} = 18.97ms^{-1}\)