Find the equation of the line which passes through (-4, 3) and parallel to line y = 2x + 5.
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Correct Answer: Option A
Explanation:
The gradient of the line y = 2x + 5 ;
\(\frac{\mathrm d y}{\mathrm d x} = 2\)
\(\frac{y - 3}{x - (-4)} = \frac{y-3}{x+4} = 2\)
\(y - 3 = 2(x + 4) \implies y = 2x + 11\)
The gradient of the line y = 2x + 5 ;
\(\frac{\mathrm d y}{\mathrm d x} = 2\)
\(\frac{y - 3}{x - (-4)} = \frac{y-3}{x+4} = 2\)
\(y - 3 = 2(x + 4) \implies y = 2x + 11\)