Forces \(F_{1} = (8N, 030°)\) and \(F_{2} = (10N, 150°)\) act on a particle. Find the horizontal component of the resultant force.
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Correct Answer: Option A
Explanation:
\(F = F \cos \theta + F \sin \theta\)
where \(F \cos \theta = \text{horizontal component}\)
\(F \sin \theta = \text{vertical component}\)
Horizontal component of resultant = sum of horizontal compoents of individual forces
= \(8 \cos 30 + 10 \cos 150 = 6.928 - 8.66 \approxeq - 1.7N\)
\(F = F \cos \theta + F \sin \theta\)
where \(F \cos \theta = \text{horizontal component}\)
\(F \sin \theta = \text{vertical component}\)
Horizontal component of resultant = sum of horizontal compoents of individual forces
= \(8 \cos 30 + 10 \cos 150 = 6.928 - 8.66 \approxeq - 1.7N\)