A line passes through the origin and the point \((1\frac{1}{4}, 2\frac{1}{2})\). Find the y-coordinate of the line when x = 4.
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Correct Answer: Option D
Explanation:
The gradient of the equation = \(\frac{y_{1} - y_{0}}{x_{1} - x_{0}} = \frac{\frac{5}{2} - 0}{\frac{5}{4} - 0}\)
= \(\frac{\frac{5}{2}}{\frac{5}{4}} = 2\)
The line passes through the origin, therefore the equation of the line is y = mx
\(y = 2x\)
When x = 4, y = 2 x 4 = 8.
The gradient of the equation = \(\frac{y_{1} - y_{0}}{x_{1} - x_{0}} = \frac{\frac{5}{2} - 0}{\frac{5}{4} - 0}\)
= \(\frac{\frac{5}{2}}{\frac{5}{4}} = 2\)
The line passes through the origin, therefore the equation of the line is y = mx
\(y = 2x\)
When x = 4, y = 2 x 4 = 8.