Solve: \(2\cos x - 1 = 0\).
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Correct Answer: Option D
Explanation:
\(2\cos x - 1 = 0 \implies 2\cos x = 1\)
\(\cos x = \frac{1}{2}\)
\(x = \cos^{-1} (\frac{1}{2})\)
= \(\frac{\pi}{3}\) = \(\frac{5\pi}{3}\)
\(2\cos x - 1 = 0 \implies 2\cos x = 1\)
\(\cos x = \frac{1}{2}\)
\(x = \cos^{-1} (\frac{1}{2})\)
= \(\frac{\pi}{3}\) = \(\frac{5\pi}{3}\)