A particle accelerates at 12\(ms^{-2}\) and travels a distance of 250m in 6 seconds. Find the initial velocity of the particle.
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Correct Answer: Option A
Explanation:
\(s = ut + \frac{1}{2}at^{2}\)
\(250 = 6u + \frac{1}{2}(12)(6^{2})\)
\(250 = 6u + 216 \implies 6u = 250 - 216 = 34\)
\(u = \frac{34}{6} \approxeq 5.7ms^{-1}\)
\(s = ut + \frac{1}{2}at^{2}\)
\(250 = 6u + \frac{1}{2}(12)(6^{2})\)
\(250 = 6u + 216 \implies 6u = 250 - 216 = 34\)
\(u = \frac{34}{6} \approxeq 5.7ms^{-1}\)