The gradient of the line passing through the points P(4, 5) and Q(x, 9) is \(\frac{1}{2}\). Find the value of x.
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option D
Explanation:
\(Gradient = \frac{y_{1} - y_{2}}{x_{1} - x_{2}} \)
\(\frac{1}{2} = \frac{5 - 9}{4 - x}\)
\(\frac{1}{2} = \frac{-4}{4 - x} \implies -8 = 4 - x\)
\(x = 4 + 8 = 12\)
\(Gradient = \frac{y_{1} - y_{2}}{x_{1} - x_{2}} \)
\(\frac{1}{2} = \frac{5 - 9}{4 - x}\)
\(\frac{1}{2} = \frac{-4}{4 - x} \implies -8 = 4 - x\)
\(x = 4 + 8 = 12\)