Simplify \(\frac{\sqrt{3} + \sqrt{48}}{\sqrt{6}}\)
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option C
Explanation:
\(\frac{\sqrt{3} + \sqrt{48}}{\sqrt{6}} = \frac{\sqrt{3} + 4\sqrt{3}}{\sqrt{6}}\)
\(\frac{5\sqrt{3}}{\sqrt{6} = \frac{5\sqrt{3} \times \sqrt{6}}{\sqrt{6} \times \sqrt{6}}\)
\(\frac{5\sqrt{18}{6} = \frac{15\sqrt{2}}{6}\)
= \(\frac{5\sqrt{2}}{2}\)
\(\frac{\sqrt{3} + \sqrt{48}}{\sqrt{6}} = \frac{\sqrt{3} + 4\sqrt{3}}{\sqrt{6}}\)
\(\frac{5\sqrt{3}}{\sqrt{6} = \frac{5\sqrt{3} \times \sqrt{6}}{\sqrt{6} \times \sqrt{6}}\)
\(\frac{5\sqrt{18}{6} = \frac{15\sqrt{2}}{6}\)
= \(\frac{5\sqrt{2}}{2}\)