| Marks | 2 | 3 | 4 | 5 | 6 | 7 | 8 |
| No of students | 5 | 7 | 9 | 6 | 3 | 6 | 4 |
The table above shows the distribution of marks by some candidates in a test. Find, correct to one decimal place, the mean of the distribution.
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Correct Answer: Option D
Explanation:
Mean \(\bar{x} = \frac{\sum fx}{\sum f} = \frac{189}{40}\)
= \(4.725 \approxeq 4.7\)
| Marks(\(x\) | 2 | 3 | 4 | 5 | 6 | 7 | 8 | Total |
| Frequency \(f\) | 5 | 7 | 9 | 6 | 3 | 6 | 4 | 40 |
| \(fx\) | 10 | 21 | 36 | 30 | 18 | 42 | 32 | 189 |
Mean \(\bar{x} = \frac{\sum fx}{\sum f} = \frac{189}{40}\)
= \(4.725 \approxeq 4.7\)