A stone is projected vertically with a speed of 10 m/s from a point 8 metres above the ground. Find the maximum height reached. \([g = 10 ms^{-2}]\).
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Correct Answer: Option A
Explanation:
\(v^{2} = u^{2} + 2as\)
\(v^{2} = u^{2} - 2gs\)
\(0 = 10^{2} - 2(10)s \implies -100 = -20s\)
\(s = 5 m + 8 m = 13m\) (8m is the height from where it was thrown)
\(v^{2} = u^{2} + 2as\)
\(v^{2} = u^{2} - 2gs\)
\(0 = 10^{2} - 2(10)s \implies -100 = -20s\)
\(s = 5 m + 8 m = 13m\) (8m is the height from where it was thrown)