Eight football clubs are to play in a league on home and away basis. How many matches are possible?
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Correct Answer: Option C
Explanation:
Number of matches possible = \(2 \times ^{8}C_{2}\) (Home and away repitition of the matches)
= \(2 \times \frac{8!}{(8 - 2)! 2!}\)
= \(2 \times 28\)
= 56
Number of matches possible = \(2 \times ^{8}C_{2}\) (Home and away repitition of the matches)
= \(2 \times \frac{8!}{(8 - 2)! 2!}\)
= \(2 \times 28\)
= 56