A force F acts on a body of mass 12kg increases its speed from 5 m/s to 35 m/s in 5 seconds. Find the value of F.
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Correct Answer: Option C
Explanation:
\(F = ma \)
\(a = \frac{v - u}{t}\)
\(\therefore F = m(\frac{v - u}{t})\)
\(F = 12(\frac{35 - 5}{5}) = 12 \times 6 = 72 N\)
\(F = ma \)
\(a = \frac{v - u}{t}\)
\(\therefore F = m(\frac{v - u}{t})\)
\(F = 12(\frac{35 - 5}{5}) = 12 \times 6 = 72 N\)