Three defective bulbs got mixed up with seven good ones. If two bulbs are selected at random, what is the probability that both are good?
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Correct Answer: Option C
Explanation:
\(P(\text{both bulbs are good}) = \frac{7}{10} \times \frac{6}{9}\)
= \(\frac{7}{15}\)
\(P(\text{both bulbs are good}) = \frac{7}{10} \times \frac{6}{9}\)
= \(\frac{7}{15}\)