Find the axis of symmetry of the curve \(y = x^{2} - 4x - 12\).
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option C
Explanation:
The vertical line \(x = \frac{-b}{2a}\) is the axis of symmetry of the curve.
\(y = x^{2} - 4x - 12\)
\(\text{Axis of symmetry} = x = \frac{-(-4)}{2(1)} = \frac{4}{2} = 2\)
The vertical line \(x = \frac{-b}{2a}\) is the axis of symmetry of the curve.
\(y = x^{2} - 4x - 12\)
\(\text{Axis of symmetry} = x = \frac{-(-4)}{2(1)} = \frac{4}{2} = 2\)