Yomi was asked to label four seats S, R, P, Q. What is the probability he labelled them in alphabetical order?
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Correct Answer: Option A
Explanation:
The number of arrangements for the 4 letters = \(^{4}P_{4} = \frac{4!}{(4 - 4)!}\)
\(4! = 24\)
Alphabetical order is just 1 of the arrangements for the letters
= \(\frac{1}{24}\)
The number of arrangements for the 4 letters = \(^{4}P_{4} = \frac{4!}{(4 - 4)!}\)
\(4! = 24\)
Alphabetical order is just 1 of the arrangements for the letters
= \(\frac{1}{24}\)