Find \(\lim \limits_{x \to 3} \frac{x + 3}{x^{2} - x - 12}\)
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Correct Answer: Option A
Explanation:
\(\lim \limits_{x \to 3} \frac{x + 3}{x^{2} - x - 12} = \frac{3 + 3}{3^{2} - 3 - 12}\)
= \(\frac{6}{-6} = -1\)
\(\lim \limits_{x \to 3} \frac{x + 3}{x^{2} - x - 12} = \frac{3 + 3}{3^{2} - 3 - 12}\)
= \(\frac{6}{-6} = -1\)