A force of 200N acting on a body of mass 20kg initially at rest causes it to move a distance of 320m along a straight line for t secs. Find the value of t.
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Correct Answer: Option C
Explanation:
F = ma
\(200 = 20a \implies a = 10m/s^{2}\)
\(s = ut + \frac{1}{2}at^{2}\)
\(320 = (0 \times t) + \frac{1}{2} 10t^{2}\)
\(320 = 5t^{2} \implies t^{2} = 64\)
\(t = 8secs\)
F = ma
\(200 = 20a \implies a = 10m/s^{2}\)
\(s = ut + \frac{1}{2}at^{2}\)
\(320 = (0 \times t) + \frac{1}{2} 10t^{2}\)
\(320 = 5t^{2} \implies t^{2} = 64\)
\(t = 8secs\)