A fair die is tossed twice. Find the probability of obtaining a 3 and a 5.
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Correct Answer: Option D
Explanation:
P(c and e) = \(P(c) \times P(e)\)
P(3) = \(\frac{1}{6}\)
P(5) = \(\frac{1}{6}\)
P(3 and 5) = \frac{1}{6} \times \frac{1}{6} = \frac{1}{36}\)
P(c and e) = \(P(c) \times P(e)\)
P(3) = \(\frac{1}{6}\)
P(5) = \(\frac{1}{6}\)
P(3 and 5) = \frac{1}{6} \times \frac{1}{6} = \frac{1}{36}\)