Find the number of different arrangements of the word IKOTITINA.
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Correct Answer: Option A
Explanation:
IKOTITINA has 9 letters with 2Ts and 3Is. Therefore, the number of different arrangements
= \(\frac{9!}{2!3!} = \frac{9.8.7.6.5.4}{2} = 30240\)
IKOTITINA has 9 letters with 2Ts and 3Is. Therefore, the number of different arrangements
= \(\frac{9!}{2!3!} = \frac{9.8.7.6.5.4}{2} = 30240\)