\(g \circ h\) is
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:
The function \(y = g(x)\) is one- to- one but \(z = h(y)\) is not one- to- one but onto.
\(\therefore h(g(x)) = onto\)
The function \(y = g(x)\) is one- to- one but \(z = h(y)\) is not one- to- one but onto.
\(\therefore h(g(x)) = onto\)