The initial velocity of a particle of mass 0.1kg is 40 m/s in the direction of the unit vector j. The velocity of the particle changed to 30 m/s in the direction of the unit vector i. Find the change in momentum.
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Correct Answer: Option n
Explanation:
u = 40j m/s ; v = 30i m/s,
Change in momentum : \(m(v - u)\)
= \(0.1 (30i - 40j)\)
= \(3i - 4j\)
Magnitude : \(\sqrt{3^{2} + 4^{2}}\)
= \(\sqrt{25}\)
= \(5 Ns^{-1}\)
u = 40j m/s ; v = 30i m/s,
Change in momentum : \(m(v - u)\)
= \(0.1 (30i - 40j)\)
= \(3i - 4j\)
Magnitude : \(\sqrt{3^{2} + 4^{2}}\)
= \(\sqrt{25}\)
= \(5 Ns^{-1}\)