Find the constant term in the binomial expansion of (2x\(^2\) + \(\frac{1}{x^2}\))\(^4\)
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Correct Answer: Option B
Explanation:
6(2x\(^2\))\(^2\) (\(\frac{1}{x^2}\))\(^2\)
= 6 x 2
= 12
6(2x\(^2\))\(^2\) (\(\frac{1}{x^2}\))\(^2\)
= 6 x 2
= 12