A stone was dropped from the top of a building 40m high. Find, correct to one decimal place, the time it took the stone to reach the ground. [Take g = 9.8ms\(^{-2}\)]
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Correct Answer: Option A
Explanation:
s = \(\frac{1}{2}gt^2\)
40 = \(\frac{1}{2} \times 9.8 \times t^2\)
\(\frac{80}{9.8} = t^2\)
t = \(\sqrt{8.16326}\)
t ≈ 2.9 secs
s = \(\frac{1}{2}gt^2\)
40 = \(\frac{1}{2} \times 9.8 \times t^2\)
\(\frac{80}{9.8} = t^2\)
t = \(\sqrt{8.16326}\)
t ≈ 2.9 secs