Calculate the variance of \(\sqrt{2}\), (1 + \(\sqrt{2}\)) and (2 + \(\sqrt{2}\))
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Correct Answer: Option C
Explanation:
variance = \(\frac{\sum(x - \bar{x})^2}{n}\)
= \(\frac{2}{3}\)
| x | (x - \(\bar{x}\)) | (x - \(\bar{x}\)) |
| \(\sqrt{2}\)1 + \(\sqrt{2}\)2 + \(\sqrt{2}\) | -101 | 101\(\overline{2}\) |
variance = \(\frac{\sum(x - \bar{x})^2}{n}\)
= \(\frac{2}{3}\)