Find the inverse of \(\begin{pmatrix} 3 & 5 \\ 1 & 2 \end{pmatrix}\)
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:
Let A = \(\begin{pmatrix} 3 & 5 \\ 1 & 2 \end{pmatrix}\)
|A| = (3 x 2 - 5 x 1)
= 6 - 5
= 1
A\(^{-1}\) = \(\begin{pmatrix} 2 & -5 \\ -1 & 3 \end{pmatrix}\)
Let A = \(\begin{pmatrix} 3 & 5 \\ 1 & 2 \end{pmatrix}\)
|A| = (3 x 2 - 5 x 1)
= 6 - 5
= 1
A\(^{-1}\) = \(\begin{pmatrix} 2 & -5 \\ -1 & 3 \end{pmatrix}\)