If \(\frac{6x + k}{2x^2 + 7x - 15}\) = \(\frac{4}{x + 5} - \frac{2}{2x - 3}\). Find the value of k.
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Correct Answer: Option B
Explanation:
\(\frac{6x + k}{2x^2 + 7x - 15} = \frac{4}{x + 5} - \frac{2}{2x - 3}\)
6x + k = 4 (2x - 3) - 2(x + 5)
6x + k = 8x - 12 - 2x - 10
6x + k = 6x - 22
k = - 22
\(\frac{6x + k}{2x^2 + 7x - 15} = \frac{4}{x + 5} - \frac{2}{2x - 3}\)
6x + k = 4 (2x - 3) - 2(x + 5)
6x + k = 8x - 12 - 2x - 10
6x + k = 6x - 22
k = - 22