Forces F\(_1\)(10N, 090°) and F\(_2\)(20N, 210\(^o\)) and (4N,330°) act on a particle, Find, correct to one decimal place, the magnitude of the resultant force.
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Correct Answer: Option
Explanation:
F\(_1\) = (10N, 090\(^o\)), F\(_2\) = (20N, 210\(^o\))
F\(_3\) = (4N, 33\(^o\))
F\(_3\) component x - axis
= - 4 cos 60\(^o\) = - 2N
F\(_2\) along y - axis
= 20 x cos 30\(^o\) = -1.7320
\(\frac{8N}{-1.732N}\)
Resultant force
= \(\sqrt{8^2 + (-1.732)^2}\)
= \(\sqrt{65.999}\)
= 8.185N
= 8.2N
F\(_1\) = (10N, 090\(^o\)), F\(_2\) = (20N, 210\(^o\))
F\(_3\) = (4N, 33\(^o\))
F\(_3\) component x - axis
= - 4 cos 60\(^o\) = - 2N
F\(_2\) along y - axis
= 20 x cos 30\(^o\) = -1.7320
\(\frac{8N}{-1.732N}\)
Resultant force
= \(\sqrt{8^2 + (-1.732)^2}\)
= \(\sqrt{65.999}\)
= 8.185N
= 8.2N