The gradient ofy= 3x\(^2\) + 11x + 7 at P(x.y) is -1. Find the coordinates of P.
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Correct Answer: Option B
Explanation:
y= 3x\(^2\) + 11x +7;
dy/dx = 6x + 11= -1;
6x = -12;
x=-2
y= 3x\(^2\) + 11x + 7
At x-2,
y= 3(-2)\(^2\) +11(-2) + 7
= 12 - 22 + 7= -3
p(x, y) = (-2,-3)
y= 3x\(^2\) + 11x +7;
dy/dx = 6x + 11= -1;
6x = -12;
x=-2
y= 3x\(^2\) + 11x + 7
At x-2,
y= 3(-2)\(^2\) +11(-2) + 7
= 12 - 22 + 7= -3
p(x, y) = (-2,-3)