Find the value of the derivative of y = 3x\(^2\) (2x +1) with respect to x at the point x = 2.
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Correct Answer: Option B
Explanation:
y 3x\(^2\) (2x +1) = 6x\(^3\) + 3x\(^2\)
dy/dx = 18x\(^2\) + 6x
At x = 2, 18(2)\(^2\) + 6(2)
= 72 + 12 = 84
y 3x\(^2\) (2x +1) = 6x\(^3\) + 3x\(^2\)
dy/dx = 18x\(^2\) + 6x
At x = 2, 18(2)\(^2\) + 6(2)
= 72 + 12 = 84