In how many ways can 8 persons be seated on a bench if only three seats are available?
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Correct Answer: Option C
Explanation:
\(^3{P}_3\) = \(\frac{8!}{8-3}!\)
= \(\frac{(8 * 7 * 6 * 5)!}{5!}\)
= 336
\(^3{P}_3\) = \(\frac{8!}{8-3}!\)
= \(\frac{(8 * 7 * 6 * 5)!}{5!}\)
= 336