\(^{5y}{C}_2\) = 190, find the value of y
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Correct Answer: Option
Explanation:
\(^{5y}{C}_2\) = 190
\(\frac{5y(5y-1) (5y-2)!}{(5y-2)!(2)!}\) = 190
\(\frac{5y(5y-1)}{2}\) = 190
25y\(^2\) - 5y = 380
5y\(^2\) - 5y - 76 = 0
= (y-4) (5y+ 19) = 0
Either y - 4 = 0 or 5y+ 19 = 0;
y = 4 or -19/5
: y= 4
\(^{5y}{C}_2\) = 190
\(\frac{5y(5y-1) (5y-2)!}{(5y-2)!(2)!}\) = 190
\(\frac{5y(5y-1)}{2}\) = 190
25y\(^2\) - 5y = 380
5y\(^2\) - 5y - 76 = 0
= (y-4) (5y+ 19) = 0
Either y - 4 = 0 or 5y+ 19 = 0;
y = 4 or -19/5
: y= 4