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Sunday, 21 June 2026
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Mathematics Past Questions and Answers

Topic: Surface areas and Volumes of simple solids

Jamb Mathematics Questions - Surface areas and Volumes of simple solids

Question 1:
If the volume of a frustrum is given as \(V = \frac{\pi h}{3} (R^2 + Rr + r^2)\), find \(\frac{\mathrm d V}{\mathrm d R}\).
  • A \(\frac{\pi h}{3} (2R + r)\)
  • B \(2R + r + \frac{\pi h}{3}\)
  • C \(\frac{\pi h}{3} (2R^2 + r + 2r)\)
  • D \(\frac{2R^2}{3} \pi h\)
View Answer & Explanation
Question 2:
Calculate the total surface area of a cupboard which measures 12cm by 10cm by 8cm
  • A 1920cm\(^2\)
  • B 592cm\(^2\)
  • C 296cm\(^2\)
  • D 148cm\(^2\)
View Answer & Explanation
Question 3:
A cylindrical tank has a capacity of 3080m3. What is the depth of the tank if the diameter of its base is 14m? Take pi = 22/7.
  • A 23m
  • B 25m
  • C 20m
  • D 22m
View Answer & Explanation
Question 4:
The curved surface area of a cylinder 5cm high is 110cm2. Find the radius of its = \(\frac{22}{7}\)
  • A 2.6cm
  • B 3.5cm
  • C 3.6cm
  • D 7.0cm
View Answer & Explanation
Question 5:
If the volume of a frustrum is given as \(V = \frac{\pi h}{3} (R^2 + Rr + r^2)\), find \(\frac{\mathrm d V}{\mathrm d R}\).
  • A \(\frac{\pi h}{3} (2R + r)\)
  • B \(2R + r + \frac{\pi h}{3}\)
  • C \(\frac{\pi h}{3} (2R^2 + r + 2r)\)
  • D \(\frac{2R^2}{3} \pi h\)
View Answer & Explanation