Jamb Mathematics Questions - Change of subject of formula
Question 21:
Find T in terms of K, Q and S if S = 2r(\(\piQT + K)
- A \(\frac{S^2}{2 \pi r^2Q} - \frac{k}{Q}\)
- B \(\frac{S^2}{2 \pi r^2Q}\) - k
- C \(\frac{S^2}{4 \pi r^2Q} - \frac{k}{Q}\)
- D \(\frac{s^2}{4 \pi r^2Q}\)
View Answer & ExplanationQuestion 22:
Two variables x and y are such that \(\frac{dy}{dx}\) = 4x - 3 and y = 5 when x = 2. Find y in terms of x
- A 2x<sup style='font-size: smaller;'>2</sup> - 3x + 5
- B 2x<sup style='font-size: smaller;'>2</sup> - 3x + 3
- C 2x<sup style='font-size: smaller;'>2</sup> - 3x
- D 4
View Answer & ExplanationQuestion 23:
Make F the subject of the formula t = \(\sqrt{\frac{v}{\frac{1}{f} + \frac{1}{g}}}\)
- A \(\frac{gv-t^2}{gt^2}\)
- B \(\frac{gt^2}{gv-t^2}\)
- C \(\frac{v}{\frac{1}{t^2} - \frac{1}{g}}\)
- D \(\frac{gv}{t^2 - g}\)
View Answer & ExplanationQuestion 24:
If b3 = a-2 and c\(\frac{1}{3}\) = a\(\frac{1}{2}\)b, express c in terms of a
- A A<sup style='font-size: smaller;'>-\(\frac{1}{2}\)</sup>
- B A<sup style='font-size: smaller;'>\(\frac{1}{3}\)</sup>
- C A<sup style='font-size: smaller;'>\(\frac{3}{2}\)</sup>
- D A<sup style='font-size: smaller;'>\(\frac{2}{3}\)</sup>
View Answer & ExplanationQuestion 25:
Make \(\frac{a}{x}\) the subject of formula \(\frac{x + 1}{x - a}\)
- A \(\frac{m - 1}{m + 1}\)
- B \(\frac{m + 1}{1 - m}\)
- C \(\frac{m - 1}{1 + m}\)
- D \(\frac{m + 1}{m - 1}\)
View Answer & Explanation