Jamb Mathematics Questions - Change of subject of formula
Question 26:
If dy/dx = 2x - 3 and y = 3 when x = 0, find y in terms of x.
- A 2x<sup style='font-size: smaller;'>2</sup> - 3x
- B X<sup style='font-size: smaller;'>2</sup> - 3x
- C X<sup style='font-size: smaller;'>2</sup> - 3x - 3
- D X<sup style='font-size: smaller;'>2</sup> - 3x + 3
View Answer & ExplanationQuestion 27:
Make r subject of the formula given that \(\frac{x}{r+a}=\frac{a}{r}\)
- A \(\frac{a^{2}}{(x-a)}\)
- B \(\frac{a^{2}}{(x+a)}\)
- C \(\frac{a}{x-a}\)
- D \(\frac{a}{x+a}\)
View Answer & ExplanationQuestion 28:
If \(T = 2\pi \sqrt{\frac{l}{g}}\), make g the subject of the formula
- A (4π l<sup style='font-size: smaller;'>2</sup>) / T
- B (4π<sup style='font-size: smaller;'>2</sup>l) / T<sup style='font-size: smaller;'>2</sup>
- C (4π<sup style='font-size: smaller;'>2</sup>l<sup style='font-size: smaller;'>2</sup>) / T<sup style='font-size: smaller;'>2</sup>
- D (2π√l) / T
View Answer & ExplanationQuestion 29:
Make L the subjects of the formula if \(\sqrt{\frac{42w}{5l}}\)
- A \(\sqrt{\frac{42w}{5d}}\)
- B \(\frac{42W}{5d^2}\)
- C \(\frac{42}{5dW}\)
- D \(\frac{1}{d}\sqrt{\frac{42w}{5}}\)
View Answer & Explanation