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Sunday, 21 June 2026
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Mathematics Past Questions and Answers

Topic: Polynomials

Jamb Mathematics Questions - Polynomials

Question 1:
The solution of the equation x2 - 2x = 8 is
  • A X = 0 or 2
  • B X = -2 or 4
  • C X = 2
  • D X = -4
  • E X = 2 or 4
View Answer & Explanation
Question 2:
Make q the subject of the formula in the equation \(\frac{mn}{a^2} - \frac{pq}{b^2} = 1\)
  • A \(q = \frac{b^2(mn - a^2)}{a^2 p}\)
  • B \(q = \frac{m^2 n - a^2}{p^2}\)
  • C \(q = \frac{mn - 2b^2}{a^2}\)
  • D \(q = \frac{b^2 (n^2 - ma^2)}{n}\)
View Answer & Explanation
Question 3:
If \(6x^3 + 2x^2 - 5x + 1\) divides \(x^2 - x - 1\), find the remainder.
  • A 9x + 9
  • B 2x + 6
  • C 6x + 8
  • D 5x - 3
View Answer & Explanation
Question 4:
Find the value of x and y in the simultaneous equation: 3x + y = 21; xy = 30
  • A X = 3 or 7, y = 12 or 8
  • B X = 6 or 1, y = 11 or 5
  • C X = 2 or 5, y = 15 or 6
  • D X = 1 or 5, y = 10 or 7
View Answer & Explanation
Question 5:
If \(P = (\frac{Q(R - T)}{15})^{\frac{1}{3}}\), make T the subject of the formula.
  • A \(T = \frac{15R - Q}{P^3}\)
  • B \(T = R - \frac{15P^3}{Q}\)
  • C \(T = \frac{R - 15P^3}{Q}\)
  • D \(T = \frac{R + P^3}{15Q}\)
View Answer & Explanation