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Sunday, 16 August 2026
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Physics Past Questions and Answers

Topic: Quantity of Heat

Jamb Physics Questions - Quantity of Heat

Question 6:
a calorimeter of thermal capacity 80j contains 20g of water at 25oC. Water at 100oC is added so that the final temperature of the set-ups is 50oC. The amount of water added is (Heat capacity of water = 4.18J/g/oC)
  • A 20g
  • B 25g
  • C 45g
  • D 50g
  • E 100g
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Question 7:
Heat may be transferred by conduction, convection and radiation. By which of these methods does heat travel through vacuum?
  • A Conduction only
  • B Convection only
  • C Radiation only
  • D Non of these methods
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Question 8:
If I is the current passing through a metallic resistor and H is the rate of Heat generated in the resistor at a constant temperature, then
  • A H \(\alpha\) \(\frac{1}{I}\)
  • B H \(\alpha\) \(\frac{1}{I^2}\)
  • C H \(\alpha\) \(\sqrt1\)
  • D H \(\alpha\) I<sup style='font-size: smaller;'>2</sup>
  • E None of the above
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Question 9:
250g of lead at 170oC is dropped into 100g of water at 0oC. If the final temperature is 12oC, the specific heat of lead is (specific heat of water is 4,200J/kgoC)
  • A 39.5J/kg<sup style='font-size: smaller;'>o</sup>C
  • B 50.4J/kg<sup style='font-size: smaller;'>o</sup>C
  • C 127.6J/kg<sup style='font-size: smaller;'>o</sup>C
  • D 154.6J/kg<sup style='font-size: smaller;'>o</sup>C
  • E 173.4J/kg<sup style='font-size: smaller;'>o</sup>C
View Answer & Explanation
Question 10:
An electric current of 3Aflowing through an electric heating elements of resistance 20 embedded in 1,000g of an oil raises the temperature of the oil by 10oC in 10 seconds then the specific heat capacity of the oil is
  • A 1.8Jg<sup style='font-size: smaller;'>-1</sup><sup style='font-size: smaller;'>o</sup>C
  • B 0.6Jg<sup style='font-size: smaller;'>-1</sup><sup style='font-size: smaller;'>o</sup>C
  • C 0.18Jg<sup style='font-size: smaller;'>-1</sup><sup style='font-size: smaller;'>o</sup>C
  • D 18Jg<sup style='font-size: smaller;'>-1</sup><sup style='font-size: smaller;'>o</sup>C
  • E 0.06Jg<sup style='font-size: smaller;'>-1</sup><sup style='font-size: smaller;'>o</sup>C
View Answer & Explanation