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The Potentiometer Method Of Measuring Emf Current And Internal Resistance Of A Cell - Physics Jamb Past Questions and Answers

Physics Questions And Answers On The Potentiometer Method Of Measuring Emf Current And Internal Resistance Of A Cell
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Physics Jamb Past Questions


Questions and Answers on The potentiometer method of measuring emf, current and internal resistance of a cell

Question 1 :



If the time of flight is 96seconds, calculate the horizontal range through the point of projection.

A. 84400m
B. 69000m
C. 61440m
D. 24000m


Question 2 :



if the fig above E is an accumulator with negligible internal resistance. and the EMF 9.0V, The the total current is

A. 0.3A
B. 0.8A
C. 1.0A
D. 1.8A


Question 3 :



A calibrated potentiometer is used to measure the e.m.f. of a cell because the

A. Internal resistance of a cell is small compared with that of the potentiometer
B. Potentiometer has a linear scale
C. Potentiometer takes no current from the cell
D. Resistance of the potentiometer is less than that of a voltmeter




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