The perimeter of a rectangle is 42 inches. The length is 5 inches longer and the width. Find the length and width of the rectangle?
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option B
Explanation:
\(P =2( L + W )=42\)
Where \(P =\) Perimeter
\(L =\) Length and \(W =\) widthivide both sides by 2
\(L + W =21\)
\(L = W +5\)
Put eqn (2) into (1)
\(W+5+W=21\)
\(2 W=21-5, \quad 2 W=16\)
\(W=16 / 2=8\) Inches
Put \(W=8\) into eqn (2)
\(L =8+5=13\) inches
\(P =2( L + W )=42\)
Where \(P =\) Perimeter
\(L =\) Length and \(W =\) widthivide both sides by 2
\(L + W =21\)
\(L = W +5\)
Put eqn (2) into (1)
\(W+5+W=21\)
\(2 W=21-5, \quad 2 W=16\)
\(W=16 / 2=8\) Inches
Put \(W=8\) into eqn (2)
\(L =8+5=13\) inches