In the figure above, KL//NM, LN bisects < KNM. If angles KLN is 54o and angle MKN is 35o, calculate the size of angle KMN.
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Correct Answer: Option C
Explanation:
In the diagram above, \(\alpha\) = 54o(alternate angles; KL||MN) < KNM = 2\(\alpha\) (LN is bisector of < KNM) = 108o
35o + < KMN + 108o = 180o(sum of angles of \(\bigtriangleup\))
< KMN + 143o = 180o
< KMN = 180o - 143o
= 37o
In the diagram above, \(\alpha\) = 54o(alternate angles; KL||MN) < KNM = 2\(\alpha\) (LN is bisector of < KNM) = 108o
35o + < KMN + 108o = 180o(sum of angles of \(\bigtriangleup\))
< KMN + 143o = 180o
< KMN = 180o - 143o
= 37o