A mixture of 40 liters of milk and water contains \(10 \%\) water. How much water should be added to this so that water may be \(20 \%\) in the new mixture?
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Correct Answer: Option B
Explanation:
A mixture of 40 liters of milk \(=36\) liters of Milk and 4 liters of water \(=90: 10\) ratio
Now the new mixture should be in the ratio of \(80: 20\)
Hence \(80 \%\) is equivalent to 36 liters (no addition of milk is done)
\(100 \%\) is \((36 / 80)^{*} 100=45\) liters of milk is present in the new mixture
Thus water shall be added \(=(45-36-4)=5\) liters of water
A mixture of 40 liters of milk \(=36\) liters of Milk and 4 liters of water \(=90: 10\) ratio
Now the new mixture should be in the ratio of \(80: 20\)
Hence \(80 \%\) is equivalent to 36 liters (no addition of milk is done)
\(100 \%\) is \((36 / 80)^{*} 100=45\) liters of milk is present in the new mixture
Thus water shall be added \(=(45-36-4)=5\) liters of water