The 10th term of an AP is 32. If the first term is 3/2, what is the 4th term?
Take Free Practice Test On 2026 JAMB UTME, Post UTME, WAEC SSCE, GCE, NECO SSCE
Correct Answer: Option A
Explanation:
Tn = a + (n-1)d
10th term = 32
32 = 3/2 + 9d
9d = 32 - 3/2
9d = 61/2
d = 61/18
: T4 = 3/2 + 3(61/18)
T4 = 3/2 + 61/6→ 35/3
Tn = a + (n-1)d
10th term = 32
32 = 3/2 + 9d
9d = 32 - 3/2
9d = 61/2
d = 61/18
: T4 = 3/2 + 3(61/18)
T4 = 3/2 + 61/6→ 35/3