Integrate (2x+1)\(^3\)
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Correct Answer: Option B
Explanation:
Recall chain rule:
u = 2x +1; du = 2dx→ dx =\(\frac{du}{2}\)
u\(^3\) =∫u\(^3\)\(\frac{du}{2}\)→\(\frac{1}{2}\)∫u\(^3\)
=\(\frac{1*u^4}{2*4}\)
=\(\frac{u^4}{8}\)→\(\frac{{2x+1}^4}{8}\) + C
There is an explanation video available below.
Recall chain rule:
u = 2x +1; du = 2dx→ dx =\(\frac{du}{2}\)
u\(^3\) =∫u\(^3\)\(\frac{du}{2}\)→\(\frac{1}{2}\)∫u\(^3\)
=\(\frac{1*u^4}{2*4}\)
=\(\frac{u^4}{8}\)→\(\frac{{2x+1}^4}{8}\) + C
There is an explanation video available below.