If sec\(^2\)θ + tan\(^2\)θ = 3, then the angleθ is equal to?
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Correct Answer: Option C
Explanation:
Given that sec\(^2\)θ + tan\(^2\)θ = 3
Where sec\(^2\)θ= 1 + tan\(^2\)θ
: 1 + tan\(^2\)θ + tan\(^2\)θ = 3
2tan\(^2\)θ = 3 - 1
2tan\(^2\)θ = 2
divide both sides by 2
tan\(^2\)θ = 1
tanθ=√1
tanθ= 1
θ = tan\(^{-1}\) (1)
θ = 45º
Given that sec\(^2\)θ + tan\(^2\)θ = 3
Where sec\(^2\)θ= 1 + tan\(^2\)θ
: 1 + tan\(^2\)θ + tan\(^2\)θ = 3
2tan\(^2\)θ = 3 - 1
2tan\(^2\)θ = 2
divide both sides by 2
tan\(^2\)θ = 1
tanθ=√1
tanθ= 1
θ = tan\(^{-1}\) (1)
θ = 45º