A student is using a graduated cylinder to measure the volume of water and reports a reading of 18 mL. The teacher reports the value as 18.4 mL. What is the student's percent error?
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Correct Answer: Option A
Explanation:
% error = \(\frac{Error}{Actual Value}\) x 100%
Student's Value = 18mL
Actual Value = 18.4mL
Error = 18.4 - 18 = 0.4
∴ % error = \(\frac{0.4}{18.4}\) x 100% = 2.17%
% error = \(\frac{Error}{Actual Value}\) x 100%
Student's Value = 18mL
Actual Value = 18.4mL
Error = 18.4 - 18 = 0.4
∴ % error = \(\frac{0.4}{18.4}\) x 100% = 2.17%