Calculate the area of the composite figure above.
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Correct Answer: Option B
Explanation:
Area of the composite figure = Area of semi circle + Area of rectangle + Area of triangle
Area of semi circle = \(\frac{1}{2}\pi r^2 = \frac{1}{2}\times\pi\times\frac{d^2}{4} = \frac{1}{2}\times\frac{22}{7}\times\frac{42^2}{4} = 693 m^2\)
Area of rectangle = l x b = 42 x 60 =2520 m\(^2\)
Area of triangle = \(\frac{1}{2}\times b \times h = \frac{1}{2}\times 36 \times 42 = 756 m^2\)
∴ Area of the composite figure = 693 + 2520 + 756 = 3969 m\(^2\)
Area of the composite figure = Area of semi circle + Area of rectangle + Area of triangle
Area of semi circle = \(\frac{1}{2}\pi r^2 = \frac{1}{2}\times\pi\times\frac{d^2}{4} = \frac{1}{2}\times\frac{22}{7}\times\frac{42^2}{4} = 693 m^2\)
Area of rectangle = l x b = 42 x 60 =2520 m\(^2\)
Area of triangle = \(\frac{1}{2}\times b \times h = \frac{1}{2}\times 36 \times 42 = 756 m^2\)
∴ Area of the composite figure = 693 + 2520 + 756 = 3969 m\(^2\)