Calculate the mean deviation of the first five prime numbers.
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Correct Answer: Option A
Explanation:
The first five prime numbers are 2, 3, 5, 7 and 11
M.D = \(\frac {\sum (x - x̄)}{n}\)
n = 5
\(x̄ = \frac {\sum x}{n} = \frac {2 + 3 + 5 + 7 + 11}{5} = \frac {28}{5} = 5.6\)
M.D = \(\frac {(2 - 5.6) + (3 - 5.6) + (5 - 5.6) + (7 - 5.6) + (11 - 5.6)}{5}\)
= \(\frac {(-3.6) + (-2.6) + (-0.6) + (1.4) + (5.4)}{5} = \frac {13.6}{5}\)
Take the absolute value of all numbers in bracket
= \(\frac {3.6 + 2.6 + 0.6 + 1.4 + 5.4}{5} = \frac {13.6}{5}\)
\(\therefore M.D = 2.72\)
The first five prime numbers are 2, 3, 5, 7 and 11
M.D = \(\frac {\sum (x - x̄)}{n}\)
n = 5
\(x̄ = \frac {\sum x}{n} = \frac {2 + 3 + 5 + 7 + 11}{5} = \frac {28}{5} = 5.6\)
M.D = \(\frac {(2 - 5.6) + (3 - 5.6) + (5 - 5.6) + (7 - 5.6) + (11 - 5.6)}{5}\)
= \(\frac {(-3.6) + (-2.6) + (-0.6) + (1.4) + (5.4)}{5} = \frac {13.6}{5}\)
Take the absolute value of all numbers in bracket
= \(\frac {3.6 + 2.6 + 0.6 + 1.4 + 5.4}{5} = \frac {13.6}{5}\)
\(\therefore M.D = 2.72\)