If \(f(x) = 3x^3 + 4x^2 + x - 8\), what is the value of f(-2)?
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Correct Answer: Option C
Explanation:
\(f(x) = 3x^3 + 4x^2 + x - 8\)
\(f(-2) = 3(-2)^3 + 4(-2)^2 + (-2) - 8\)
= \(-24 + 16 - 2 - 8\)
= -18
\(f(x) = 3x^3 + 4x^2 + x - 8\)
\(f(-2) = 3(-2)^3 + 4(-2)^2 + (-2) - 8\)
= \(-24 + 16 - 2 - 8\)
= -18