The weight of a day-old chick was measured to be 0.21g. If the actual weight of the chick is 0.18g, what was the percentage error in the measurement?
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Correct Answer: Option D
Explanation:
Actual weight = 0.18g
Error = 0.21g - 0.18g
= 0.03g
% error = \(\frac{0.03}{0.18} \times 100%\)
= 16.7%
Actual weight = 0.18g
Error = 0.21g - 0.18g
= 0.03g
% error = \(\frac{0.03}{0.18} \times 100%\)
= 16.7%